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Popular >

integral of-0.04t

Solution

\int - 0.04 t d t

Solution

- 0.02 t^{2} + C

Solution steps

\int - 0.04 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 0.04 \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= - 0.04 \cdot \frac{t ^{2}}{2}

Simplify

- 0.04 \cdot \frac{t ^{2}}{2} : - 0.02 t^{2}

= - 0.02 t^{2}

Add a constant to the solution

= - 0.02 t^{2} + C

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Frequently Asked Questions (FAQ)

What is the integral of-0.04t ?
The integral of-0.04t is -0.02t^2+C