What is the derivative of f(x)=(699)/((x+1)^{0.94)} ?

The derivative of f(x)=(699)/((x+1)^{0.94)} is -(657.06)/((x+1)^{1.94)}

What is the first derivative of f(x)=(699)/((x+1)^{0.94)} ?

The first derivative of f(x)=(699)/((x+1)^{0.94)} is -(657.06)/((x+1)^{1.94)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{699}{( x + 1 ) ^{0.94}}

- \frac{657.06}{( x + 1 ) ^{1.94}}

Solution steps

\frac{d}{d x} (\frac{699}{( x + 1 ) ^{0.94}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 699 \frac{d}{d x} (\frac{1}{( x + 1 ) ^{0.94}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 699 \frac{d}{d x} ((x + 1)^{- 0.94})

Apply the chain rule:

- \frac{0.94}{( x + 1 ) ^{1.94}} \frac{d}{d x} (x + 1)

= - \frac{0.94}{( x + 1 ) ^{1.94}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 699 (- \frac{0.94}{( x + 1 ) ^{1.94}} \cdot 1)

Simplify

699 (- \frac{0.94}{( x + 1 ) ^{1.94}} \cdot 1) : - \frac{657.06}{( x + 1 ) ^{1.94}}

= - \frac{657.06}{( x + 1 ) ^{1.94}}

\int_{- \frac{1}{2}}^{0} x^{4} \cdot e^{2 x + 1} d x

x \to \infty lim (\frac{x}{c})

\int e^{n x} d x

\frac{d}{d x} (x^{4} - 8 x^{2} - 4)

What is the derivative of f(x)=(699)/((x+1)^{0.94)} ?
The derivative of f(x)=(699)/((x+1)^{0.94)} is -(657.06)/((x+1)^{1.94)}
What is the first derivative of f(x)=(699)/((x+1)^{0.94)} ?
The first derivative of f(x)=(699)/((x+1)^{0.94)} is -(657.06)/((x+1)^{1.94)}