What is the integral from 1 to 4 of (x^2) ?

The integral from 1 to 4 of (x^2) is 21

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integral from 1 to 4 of (x^2)

\int_{1}^{4} (x^{2}) d x

21

Solution steps

\int_{1}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{4}

= [\frac{x ^{3}}{3}]_{1}^{4}

Compute the boundaries:

21

= 21

\int_{1}^{3} 1 + \frac{1}{x ^{2}} d x

n = 0 \sum \infty 0. 4^{n}

\frac{d}{d x} (e^{- x^{2} + 7 x})

y^{^{''}} + 1.875 y^{^{'}} + 0.125 y = 0, y (0) = 2, y^{^{'}} (0) = 1

\frac{d}{d x} (4 π)

What is the integral from 1 to 4 of (x^2) ?
The integral from 1 to 4 of (x^2) is 21