What is the integral of (sin(x))^4 ?

The integral of (sin(x))^4 is -1/4 sin^3(x)cos(x)+3/8 (x-1/2 sin(2x))+C

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integral of (sin(x))^4

\int (sin (x))^{4} d x

- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)) + C

Solution steps

\int (sin (x))^{4} d x

Simplify

= \int sin^{4} (x) d x

Apply Integral Reduction

= - \frac{cos ( x ) sin ^{3} ( x )}{4} + \frac{3}{4} \cdot \int sin^{2} (x) d x

\int sin^{2} (x) d x = \frac{1}{2} (x - \frac{1}{2} sin (2 x))

= - \frac{cos ( x ) sin ^{3} ( x )}{4} + \frac{3}{4} \cdot \frac{1}{2} (x - \frac{1}{2} sin (2 x))

Simplify

- \frac{cos ( x ) sin ^{3} ( x )}{4} + \frac{3}{4} \cdot \frac{1}{2} (x - \frac{1}{2} sin (2 x)) : - \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x))

= - \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x))

Add a constant to the solution

= - \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)) + C

x^{(\frac{1}{3})}, 8

\int 2 x x^{2} + 4 d x

\int \frac{1}{x ^{2} + 81} d x

\int_{1}^{x} 1 + 2 t d t

What is the integral of (sin(x))^4 ?
The integral of (sin(x))^4 is -1/4 sin^3(x)cos(x)+3/8 (x-1/2 sin(2x))+C