What is the integral of xarcsin(2)x^2 ?

The integral of xarcsin(2)x^2 is 1/4 arcsin(2)x^4+C

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integral of xarcsin(2)x^2

\int x arcsin (2) x^{2} d x

\frac{1}{4} arcsin (2) x^{4} + C

Solution steps

\int x arcsin (2) x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= arcsin (2) \cdot \int x x^{2} d x

Simplify

x x^{2} : x^{3}

= arcsin (2) \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= arcsin (2) \frac{x ^{4}}{4}

Simplify

arcsin (2) \frac{x ^{4}}{4} : \frac{1}{4} arcsin (2) x^{4}

= \frac{1}{4} arcsin (2) x^{4}

Add a constant to the solution

= \frac{1}{4} arcsin (2) x^{4} + C

\frac{d y}{d x} = y^{\frac{2}{3}}

\int_{0}^{1} \frac{69}{x ^{5}} d x

5 t sin (π t)

y = e^{2 x}, y = e^{3 x}, x = 1

x \to - 6 lim (- 5 x - 6)

What is the integral of xarcsin(2)x^2 ?
The integral of xarcsin(2)x^2 is 1/4 arcsin(2)x^4+C