What is the derivative of 1-log_{e}(x) ?

The derivative of 1-log_{e}(x) is -1/x

What is the first derivative of 1-log_{e}(x) ?

The first derivative of 1-log_{e}(x) is -1/x

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derivative of

1 - lo g_{e} (x)

- \frac{1}{x}

Solution steps

\frac{d}{d x} (1 - lo g_{e} (x))

Simplify

1 - lo g_{e} (x) : 1 - ln (x)

= \frac{d}{d x} (1 - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (ln (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 - \frac{1}{x}

Simplify

= - \frac{1}{x}

\frac{\partial}{\partial z} (\frac{2 x - 2 z}{3 y + 2 z})

\int \frac{4 x}{x ^{2} + 4 x + 4} d x

\frac{d y}{d x} - \frac{4}{x} y = 2 x^{5} e^{\frac{y}{x ^{4}}}

y^{2} = x + 6, y^{2} = 6 - x

\int - 3 x + 2 x d x

What is the derivative of 1-log_{e}(x) ?
The derivative of 1-log_{e}(x) is -1/x
What is the first derivative of 1-log_{e}(x) ?
The first derivative of 1-log_{e}(x) is -1/x