What is (\partial)/(\partial x)(cos(2x+y)) ?

The answer to (\partial)/(\partial x)(cos(2x+y)) is -sin(2x+y)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(cos(2x+y))

\frac{\partial}{\partial x} (cos (2 x + y))

- sin (2 x + y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (cos (2 x + y))

Treat

y

as a constant

Apply the chain rule:

- sin (2 x + y) \frac{\partial}{\partial x} (2 x + y)

= - sin (2 x + y) \frac{\partial}{\partial x} (2 x + y)

\frac{\partial}{\partial x} (2 x + y) = 2

= - sin (2 x + y) \cdot 2

\frac{d}{d x} (3 x^{2} + 8 x)

x \to 1 lim (\frac{x + 6}{x + 1})

x \to 1 lim (arctan (ln (x)))

\frac{d}{d x} (4 x^{3} - 5 x^{2} + ln (x))

y^{2} - 2 x = 1, x - y = 1

What is (\partial)/(\partial x)(cos(2x+y)) ?
The answer to (\partial)/(\partial x)(cos(2x+y)) is -sin(2x+y)*2