What is the derivative of-(2x/((x^2+4)^2)) ?

The derivative of-(2x/((x^2+4)^2)) is -(2(-3x^2+4))/((x^2+4)^3)

What is the first derivative of-(2x/((x^2+4)^2)) ?

The first derivative of-(2x/((x^2+4)^2)) is -(2(-3x^2+4))/((x^2+4)^3)

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\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 4 ) ^{2}})

- \frac{2 ( - 3 x ^{2} + 4 )}{( x ^{2} + 4 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 4 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{x}{( x ^{2} + 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 4 ) ^{2} ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 4)^{2}) = 4 x (x^{2} + 4)

= - 2 \cdot \frac{1 \cdot ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

Simplify

- 2 \cdot \frac{1 \cdot ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) x}{( ( x ^{2} + 4 ) ^{2} ) ^{2}} : - \frac{2 ( - 3 x ^{2} + 4 )}{( x ^{2} + 4 ) ^{3}}

= - \frac{2 ( - 3 x ^{2} + 4 )}{( x ^{2} + 4 ) ^{3}}

\int x^{5} sin (3 + x^{\frac{7}{2}}) d x

\frac{\partial}{\partial y} (ln (\frac{x + y}{x - y}))

f (x) = \frac{7}{x}, at x = 2 or, x = 7

\int \frac{2 cos ( x )}{sin ( x )} d x

\frac{d}{d x} (x^{2} + 4 y, 3 x)

What is the derivative of-(2x/((x^2+4)^2)) ?
The derivative of-(2x/((x^2+4)^2)) is -(2(-3x^2+4))/((x^2+4)^3)
What is the first derivative of-(2x/((x^2+4)^2)) ?
The first derivative of-(2x/((x^2+4)^2)) is -(2(-3x^2+4))/((x^2+4)^3)