What is the derivative of x^2+4y,3x ?

The derivative of x^2+4y,3x is 2x+(4,3((dy)/(dx)x+1*y))

What is the first derivative of x^2+4y,3x ?

The first derivative of x^2+4y,3x is 2x+(4,3((dy)/(dx)x+1*y))

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\frac{d}{d x} (x^{2} + 4 y, 3 x)

2 x + (4, 3 (\frac{d y}{d x} x + 1 \cdot y))

Solution steps

\frac{d}{d x} (x^{2} + 4 y, 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 y, 3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 y, 3 x) = (4, 3 (\frac{d y}{d x} x + 1 \cdot y))

= 2 x + (4, 3 (\frac{d y}{d x} x + 1 \cdot y))

\int_{0}^{\frac{π}{2}} cos^{3} (15 x) d x

\frac{d}{d x} (11 arctan (x))

\int \frac{1}{tan ( u )} d u

x \to \infty lim (1 - x)

sin (2 (t - \frac{5 π}{2}))

What is the derivative of x^2+4y,3x ?
The derivative of x^2+4y,3x is 2x+(4,3((dy)/(dx)x+1*y))
What is the first derivative of x^2+4y,3x ?
The first derivative of x^2+4y,3x is 2x+(4,3((dy)/(dx)x+1*y))