What is laplacetransform sin(2(t-(5pi)/2)) ?

The answer to laplacetransform sin(2(t-(5pi)/2)) is -2/(s^2+4)

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laplacetransform sin(2(t-(5pi)/2))

laplace transform

sin (2 (t - \frac{5 π}{2}))

- \frac{2}{s ^{2} + 4}

Solution steps

L {sin (2 (t - \frac{5 π}{2}))}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (2 (t - \frac{5 π}{2}))} = \frac{s sin ( - 5 π ) + 2 cos ( - 5 π )}{s ^{2} + 2 ^{2}}

= \frac{s sin ( - 5 π ) + 2 cos ( - 5 π )}{s ^{2} + 2 ^{2}}

= - \frac{2}{s ^{2} + 4}

\frac{d}{d x} (6 - 9 x)

f (x) = e^{4 x} cos (7 x)

sin (4 t + 5)

f (x) = - x^{3}, (- 2, 8)

\int cos (x^{2}) 2 x d x

What is laplacetransform sin(2(t-(5pi)/2)) ?
The answer to laplacetransform sin(2(t-(5pi)/2)) is -2/(s^2+4)