What is the integral from-infinity to 0 of 9^x ?

The integral from-infinity to 0 of 9^x is 1/(2ln(3))

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integral from-infinity to 0 of 9^x

\int_{- \infty}^{0} 9^{x} d x

\frac{1}{2 ln ( 3 )}

Decimal Notation

0.45511 \dots

Solution steps

\int_{- \infty}^{0} 9^{x} d x

Compute the indefinite integral:

\int 9^{x} d x = \frac{9 ^{x}}{2 ln ( 3 )} + C

Compute the boundaries:

\int_{- \infty}^{0} 9^{x} d x = \frac{1}{2 ln ( 3 )} - 0

= \frac{1}{2 ln ( 3 )} - 0

Simplify

= \frac{1}{2 ln ( 3 )}

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x (\frac{d y}{d x}) = y + x^{2} - y^{2}

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\frac{\partial}{\partial x} (3 x z)

What is the integral from-infinity to 0 of 9^x ?
The integral from-infinity to 0 of 9^x is 1/(2ln(3))