What is the derivative of 1/3 x^3-2x^2+3x-4 ?

The derivative of 1/3 x^3-2x^2+3x-4 is x^2-4x+3

What is the first derivative of 1/3 x^3-2x^2+3x-4 ?

The first derivative of 1/3 x^3-2x^2+3x-4 is x^2-4x+3

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derivative of

\frac{1}{3} x^{3} - 2 x^{2} + 3 x - 4

x^{2} - 4 x + 3

Solution steps

\frac{d}{d x} (\frac{1}{3} x^{3} - 2 x^{2} + 3 x - 4)

Simplify

\frac{1}{3} x^{3} - 2 x^{2} + 3 x - 4 : \frac{x ^{3}}{3} - 2 x^{2} + 3 x - 4

= \frac{d}{d x} (\frac{x ^{3}}{3} - 2 x^{2} + 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= x^{2} - 4 x + 3 - 0

Simplify

= x^{2} - 4 x + 3

x \to \infty lim (1 + \frac{8}{x})

8 x^{2} e^{x}

\frac{d}{d x} (1 - 121 x^{2} arccos (11 x))

\frac{s}{s ^{2} + 64}

\int (x^{3} - 4 x - 6) d x

What is the derivative of 1/3 x^3-2x^2+3x-4 ?
The derivative of 1/3 x^3-2x^2+3x-4 is x^2-4x+3
What is the first derivative of 1/3 x^3-2x^2+3x-4 ?
The first derivative of 1/3 x^3-2x^2+3x-4 is x^2-4x+3