What is the integral of 3cos(x)y+5x^4z^2 ?

The integral of 3cos(x)y+5x^4z^2 is 3ysin(x)+z^2x^5+C

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integral of 3cos(x)y+5x^4z^2

\int 3 cos (x) y + 5 x^{4} z^{2} d x

3 y sin (x) + z^{2} x^{5} + C

Solution steps

\int 3 cos (x) y + 5 x^{4} z^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 cos (x) y d x + \int 5 z^{2} x^{4} d x

\int 3 cos (x) y d x = 3 y sin (x)

\int 5 z^{2} x^{4} d x = z^{2} x^{5}

= 3 y sin (x) + z^{2} x^{5}

Add a constant to the solution

= 3 y sin (x) + z^{2} x^{5} + C

\int e^{x + s i n (y)} cos (y) d y

\frac{d}{d x} (x^{2} - 4 x - 5)

n = 1 \sum \infty \frac{1}{n \cdot ( n + 1 )}

\int \frac{1 + x}{- x x} d x

\int_{0}^{1} - (x^{2} - x) d x

What is the integral of 3cos(x)y+5x^4z^2 ?
The integral of 3cos(x)y+5x^4z^2 is 3ysin(x)+z^2x^5+C