What is (\partial)/(\partial x)(y^2+2x^2-y) ?

The answer to (\partial)/(\partial x)(y^2+2x^2-y) is 4x

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(\partial)/(\partial x)(y^2+2x^2-y)

\frac{\partial}{\partial x} (y^{2} + 2 x^{2} - y)

4 x

Solution steps

\frac{\partial}{\partial x} (y^{2} + 2 x^{2} - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y) = 0

= 0 + 4 x - 0

Simplify

= 4 x

\int_{1}^{2} \frac{1}{x ( ln ( x ) ) ^{p}} d x

f (x) = ln (3 x e^{- x})

\frac{f ( x )}{x ^{5}}

\frac{\partial}{\partial x} (sin (x^{2} + y^{3}))

\int - \frac{1}{4 - x} d x

What is (\partial)/(\partial x)(y^2+2x^2-y) ?
The answer to (\partial)/(\partial x)(y^2+2x^2-y) is 4x