What is the derivative of 8arcsin(x^4) ?

The derivative of 8arcsin(x^4) is (32x^3)/(sqrt(1-x^8))

What is the first derivative of 8arcsin(x^4) ?

The first derivative of 8arcsin(x^4) is (32x^3)/(sqrt(1-x^8))

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\frac{d}{d x} (8 arcsin (x^{4}))

\frac{32 x ^{3}}{1 - x ^{8}}

Solution steps

\frac{d}{d x} (8 arcsin (x^{4}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (arcsin (x^{4}))

Apply the chain rule:

\frac{1}{1 - ( x ^{4} ) ^{2}} \frac{d}{d x} (x^{4})

= \frac{1}{1 - ( x ^{4} ) ^{2}} \frac{d}{d x} (x^{4})

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 8 \cdot \frac{1}{1 - ( x ^{4} ) ^{2}} \cdot 4 x^{3}

Simplify

8 \cdot \frac{1}{1 - ( x ^{4} ) ^{2}} \cdot 4 x^{3} : \frac{32 x ^{3}}{1 - x ^{8}}

= \frac{32 x ^{3}}{1 - x ^{8}}

\frac{\partial}{\partial x} (4 x^{2} + 4 y^{2})

y^{^{'}} + 5 y = x

\frac{d}{d x} (x^{3} - 3 x^{2} + 3)

\frac{d}{d x} (e^{x} - x^{3} - 7)

\frac{d}{d x} (60 x^{2})

What is the derivative of 8arcsin(x^4) ?
The derivative of 8arcsin(x^4) is (32x^3)/(sqrt(1-x^8))
What is the first derivative of 8arcsin(x^4) ?
The first derivative of 8arcsin(x^4) is (32x^3)/(sqrt(1-x^8))