What is the sum from n=0 to infinity of p^k ?

The sum from n=0 to infinity of p^k is Radius of convergence is 1, Interval of convergence is-1<p<1

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sum from n=0 to infinity of p^k

n = 0 \sum \infty p^{k}

Radius of convergence is 1, Interval of convergence is - 1 < p < 1

Solution steps

n = 0 \sum \infty p^{k}

Use the Root Test to compute the convergence interval

Radius of convergence is 1, Interval of convergence is - 1 < p < 1

n = 1 \sum \infty \frac{n - 8}{n + 8}

\int (e^{x} + a^{x}) d x

\int \frac{1}{( 1 + x )} d x

\int_{0}^{π} sin (2 x) cos (x) d x

y^{^{''}} - y^{^{'}} = 3 x^{2} e^{x}

What is the sum from n=0 to infinity of p^k ?
The sum from n=0 to infinity of p^k is Radius of convergence is 1, Interval of convergence is-1<p<1