What is the derivative of \sqrt[3]{x-9} ?

The derivative of \sqrt[3]{x-9} is 1/(3(x-9)^{2/3)}

What is the first derivative of \sqrt[3]{x-9} ?

The first derivative of \sqrt[3]{x-9} is 1/(3(x-9)^{2/3)}

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\frac{1}{3 ( x - 9 ) ^{\frac{2}{3}}}

Solution steps

Apply the chain rule:

\frac{1}{3 ( x - 9 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 9)

= \frac{1}{3 ( x - 9 ) ^{\frac{2}{3}}} \frac{d}{d x} (x - 9)

\frac{d}{d x} (x - 9) = 1

= \frac{1}{3 ( x - 9 ) ^{\frac{2}{3}}} \cdot 1

Simplify

= \frac{1}{3 ( x - 9 ) ^{\frac{2}{3}}}

\int (yz e^{x z}) d x

t \frac{d y}{d t} + 3 y = 9 t

\int (x + 3) x d x

7 x, \frac{1}{x}, x

f (x) = x^{4} - 25 x^{2} + 144, at x = - 2

What is the derivative of \sqrt[3]{x-9} ?
The derivative of \sqrt[3]{x-9} is 1/(3(x-9)^{2/3)}
What is the first derivative of \sqrt[3]{x-9} ?
The first derivative of \sqrt[3]{x-9} is 1/(3(x-9)^{2/3)}