What is the tangent of f(x)=x^4-25x^2+144,\at x=-2 ?

The tangent of f(x)=x^4-25x^2+144,\at x=-2 is y=68x+196

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^4-25x^2+144,\at x=-2

tangent of

f (x) = x^{4} - 25 x^{2} + 144, at x = - 2

y = 68 x + 196

Solution steps

Find the tangent point:

(- 2, 60)

Find the slope of

f (x) = x^{4} - 25 x^{2} + 144 : \frac{df ( x )}{d x} = 4 x^{3} - 50 x

Compute the slope of

f (x) = x^{4} - 25 x^{2} + 144

x = - 2 : m = 68

Find the line with slope m=

68

and passing through

(- 2, 60) : y = 68 x + 196

y = 68 x + 196

\frac{d}{d x} (sech (ln (x^{2})))

\int_{0}^{1} arctan (5 x + 3) d x

f (x) = \frac{2 x}{x + 2}, (2, 1)

\frac{1}{( ( s + 1 ) ^{2} + 4 )}

\int sin^{5} (t co) s^{4} t d t

What is the tangent of f(x)=x^4-25x^2+144,\at x=-2 ?
The tangent of f(x)=x^4-25x^2+144,\at x=-2 is y=68x+196