What is the derivative of f(x)=3x-ln(x^4) ?

The derivative of f(x)=3x-ln(x^4) is 3-4/x

What is the first derivative of f(x)=3x-ln(x^4) ?

The first derivative of f(x)=3x-ln(x^4) is 3-4/x

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derivative of

f (x) = 3 x - ln (x^{4})

3 - \frac{4}{x}

Solution steps

\frac{d}{d x} (3 x - ln (x^{4}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (ln (x^{4}))

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (ln (x^{4})) = \frac{4}{x}

= 3 - \frac{4}{x}

\frac{d}{d t} (3 e^{3 t})

\int 3 cos (\frac{1}{3} x) d x

\int x^{8} - 4 x^{- 5} + 6 d x

\frac{\partial}{\partial y} (y z^{2})

x \to 0 lim (x^{2} cos (\frac{1}{x}))

What is the derivative of f(x)=3x-ln(x^4) ?
The derivative of f(x)=3x-ln(x^4) is 3-4/x
What is the first derivative of f(x)=3x-ln(x^4) ?
The first derivative of f(x)=3x-ln(x^4) is 3-4/x