What is inverse oflaplace 1/(3s) ?

The answer to inverse oflaplace 1/(3s) is 1/3 \H(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse oflaplace 1/(3s)

inverse laplace

\frac{1}{3 s}

\frac{1}{3} H (t)

Solution steps

L^{- 1} {\frac{1}{3 s}}

= L^{- 1} {\frac{1}{3} \cdot \frac{1}{s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{3} L^{- 1} {\frac{1}{s}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s}} = a H (t)

Where

H (t)

is Heaviside step function

= \frac{1}{3} H (t)

\frac{\partial}{\partial x} (x^{2} y z^{2})

\frac{\partial}{\partial y} (2 x ln (y) - yz)

(e^{- x} - e^{5}) (e^{x} + e^{- 2})

y^{^{''}} - 2 y + y = t + 1, y (0) = 0, y^{^{'}} (0) = 0

f (x) = - \frac{2}{x}

What is inverse oflaplace 1/(3s) ?
The answer to inverse oflaplace 1/(3s) is 1/3 \H(t)