derivative of-2e^{5y}x-2sin(2x)

Lösung

\frac{d}{d x} (- 2 e^{5 y} x - 2 sin (2 x))

- 2 (5 e^{5 y} x \frac{d y}{d x} + e^{5 y}) - 4 cos (2 x)

Schritte zur Lösung

\frac{d}{d x} (- 2 e^{5 y} x - 2 sin (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2 e^{5 y} x) - \frac{d}{d x} (2 sin (2 x))

\frac{d}{d x} (2 e^{5 y} x) = 2 (5 e^{5 y} x \frac{d y}{d x} + e^{5 y})

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

= - 2 (5 e^{5 y} x \frac{d y}{d x} + e^{5 y}) - 4 cos (2 x)

\int_{- 2}^{2} (4 - x^{2}) d x

t a y l or (1 - x^{2})^{\frac{1}{2}}

d er i v a t i v e 6 x^{\frac{1}{2}}

\int_{0}^{6} (1497.6) (x) d x

n = 1 \sum \infty \frac{7}{4 ^{n - 1}}