What is the derivative of f(x)= x/(x^2+7) ?

The derivative of f(x)= x/(x^2+7) is (-x^2+7)/((x^2+7)^2)

What is the first derivative of f(x)= x/(x^2+7) ?

The first derivative of f(x)= x/(x^2+7) is (-x^2+7)/((x^2+7)^2)

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derivative of

f (x) = \frac{x}{x ^{2} + 7}

\frac{- x ^{2} + 7}{( x ^{2} + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x ^{2} + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} + 7 ) - \frac{d}{d x} ( x ^{2} + 7 ) x}{( x ^{2} + 7 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 7) = 2 x

= \frac{1 \cdot ( x ^{2} + 7 ) - 2 xx}{( x ^{2} + 7 ) ^{2}}

1 \cdot (x^{2} + 7) - 2 xx = - x^{2} + 7

= \frac{- x ^{2} + 7}{( x ^{2} + 7 ) ^{2}}

\frac{d}{d x} (\frac{3}{4 ( 1 - x ) ^{\frac{5}{2}}})

4 x^{2} y^{^{''}} + y = 0

\int \frac{x ^{2}}{6} d x

\frac{d}{d x} (c x cos (2 x))

\int \frac{4 + 9 x}{4} d x

What is the derivative of f(x)= x/(x^2+7) ?
The derivative of f(x)= x/(x^2+7) is (-x^2+7)/((x^2+7)^2)
What is the first derivative of f(x)= x/(x^2+7) ?
The first derivative of f(x)= x/(x^2+7) is (-x^2+7)/((x^2+7)^2)