What is the derivative of (-x^2-4/((x^2-4)^2)) ?

The derivative of (-x^2-4/((x^2-4)^2)) is -(2x(-x^2-12))/((x^2-4)^3)

What is the first derivative of (-x^2-4/((x^2-4)^2)) ?

The first derivative of (-x^2-4/((x^2-4)^2)) is -(2x(-x^2-12))/((x^2-4)^3)

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\frac{d}{d x} (\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}})

- \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{- x ^{2} - 4}{( x ^{2} - 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( - x ^{2} - 4 ) ( x ^{2} - 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} - 4 ) ^{2} ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

\frac{d}{d x} (- x^{2} - 4) = - 2 x

\frac{d}{d x} ((x^{2} - 4)^{2}) = 4 x (x^{2} - 4)

= \frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( x ^{2} - 4 ) ^{2} - 4 x ( x ^{2} - 4 ) ( - x ^{2} - 4 )}{( ( x ^{2} - 4 ) ^{2} ) ^{2}} : - \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

= - \frac{2 x ( - x ^{2} - 12 )}{( x ^{2} - 4 ) ^{3}}

(x^{2} + 4) y = 8

\int_{0.5}^{1.5} (\frac{1}{8} + \frac{3}{8} x) d x

\int (3 csc^{2} (4 x)) d x

\frac{d}{d v} (\frac{v}{u - v})

16 y^{^{''}} - y = 0

What is the derivative of (-x^2-4/((x^2-4)^2)) ?
The derivative of (-x^2-4/((x^2-4)^2)) is -(2x(-x^2-12))/((x^2-4)^3)
What is the first derivative of (-x^2-4/((x^2-4)^2)) ?
The first derivative of (-x^2-4/((x^2-4)^2)) is -(2x(-x^2-12))/((x^2-4)^3)