What is (\partial)/(\partial y)(8xsin(y-z)) ?

The answer to (\partial)/(\partial y)(8xsin(y-z)) is 8xcos(y-z)

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(\partial)/(\partial y)(8xsin(y-z))

\frac{\partial}{\partial y} (8 x sin (y - z))

8 x cos (y - z)

Solution steps

\frac{\partial}{\partial y} (8 x sin (y - z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 x \frac{\partial}{\partial y} (sin (y - z))

Apply the chain rule:

cos (y - z) \frac{\partial}{\partial y} (y - z)

= cos (y - z) \frac{\partial}{\partial y} (y - z)

\frac{\partial}{\partial y} (y - z) = 1

= 8 x cos (y - z) \cdot 1

Simplify

= 8 x cos (y - z)

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- 3

What is (\partial)/(\partial y)(8xsin(y-z)) ?
The answer to (\partial)/(\partial y)(8xsin(y-z)) is 8xcos(y-z)