What is the integral from 2 to x^3 of t^4 ?

The integral from 2 to x^3 of t^4 is (x^{15}-32)/5

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integral from 2 to x^3 of t^4

\int_{2}^{x^{3}} t^{4} d t

\frac{x ^{15} - 32}{5}

Solution steps

\int_{2}^{x^{3}} t^{4} d t

Apply the Power Rule

: [\frac{t ^{5}}{5}]_{2}^{x^{3}}

= [\frac{t ^{5}}{5}]_{2}^{x^{3}}

Compute the boundaries:

\frac{x ^{15}}{5} - \frac{32}{5}

= \frac{x ^{15}}{5} - \frac{32}{5}

Simplify

= \frac{x ^{15} - 32}{5}

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2} t

f (x) = e^{8 x}

arctan (x y)

\frac{d}{d x} (x^{3} + 7)

\int \frac{144 - x ^{2}}{x} d x

What is the integral from 2 to x^3 of t^4 ?
The integral from 2 to x^3 of t^4 is (x^{15}-32)/5