What is the d/(dθ)(2sin(θ)) ?

The d/(dθ)(2sin(θ)) is 2cos(θ)

What is the first d/(dθ)(2sin(θ)) ?

The first d/(dθ)(2sin(θ)) is 2cos(θ)

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\frac{d}{d θ} (2 sin (θ))

2 cos (θ)

Solution steps

\frac{d}{d θ} (2 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 2 cos (θ)

\frac{d}{d x} (ln (12 - x))

\frac{d}{d x} (cos^{2} (ln (x^{3} + 3 x)))

\int tan^{5} (\frac{x}{2}) d x

\frac{d}{d x} (\frac{( x ^{7} )}{x ^{14} + 1})

\int ln (x^{2} + a^{2}) d x