What is the derivative of x^4e^x-5 ?

The derivative of x^4e^x-5 is e^xx^4+4e^xx^3

What is the first derivative of x^4e^x-5 ?

The first derivative of x^4e^x-5 is e^xx^4+4e^xx^3

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derivative of

x^{4} e^{x} - 5

e^{x} x^{4} + 4 e^{x} x^{3}

Solution steps

\frac{d}{d x} (x^{4} e^{x} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4} e^{x}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{4} e^{x}) = 4 x^{3} e^{x} + e^{x} x^{4}

\frac{d}{d x} (5) = 0

= 4 x^{3} e^{x} + e^{x} x^{4} - 0

Simplify

= e^{x} x^{4} + 4 e^{x} x^{3}

\int 3 x^{2} \times 4 x^{4} d x

\int 5 x^{3} e^{- x^{2}} d x

\int \frac{1}{16 x ^{2} - 9} d x

\frac{4 x + 3}{4 x - 3}

y^{^{''}} + 36 y = e^{- t}

What is the derivative of x^4e^x-5 ?
The derivative of x^4e^x-5 is e^xx^4+4e^xx^3
What is the first derivative of x^4e^x-5 ?
The first derivative of x^4e^x-5 is e^xx^4+4e^xx^3