What is the derivative of 3x^{-2x} ?

The derivative of 3x^{-2x} is 3x^{-2x}(-2ln(x)-2)

What is the first derivative of 3x^{-2x} ?

The first derivative of 3x^{-2x} is 3x^{-2x}(-2ln(x)-2)

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derivative of

3 x^{- 2 x}

3 x^{- 2 x} (- 2 ln (x) - 2)

Solution steps

\frac{d}{d x} (3 x^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{- 2 x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

x^{- 2 x} = e^{(- 2 x) l n (x)}

= 3 \frac{d}{d x} (e^{(- 2 x) l n (x)})

Apply the chain rule:

e^{(- 2 x) l n (x)} \frac{d}{d x} ((- 2 x) ln (x))

= e^{(- 2 x) l n (x)} \frac{d}{d x} ((- 2 x) ln (x))

\frac{d}{d x} ((- 2 x) ln (x)) = - 2 ln (x) - 2

= 3 e^{(- 2 x) l n (x)} (- 2 ln (x) - 2)

Simplify

3 e^{(- 2 x) l n (x)} (- 2 ln (x) - 2) : 3 x^{- 2 x} (- 2 ln (x) - 2)

= 3 x^{- 2 x} (- 2 ln (x) - 2)

\frac{\partial}{\partial x} (\frac{m c T}{m T})

t \to 0 lim (\frac{1}{t} - \frac{1}{e ^{t} - 1})

\frac{d}{d x} (72 x)

\int x 3 - x d x

\int_{- 24}^{0} \frac{1}{1 - x} d x

What is the derivative of 3x^{-2x} ?
The derivative of 3x^{-2x} is 3x^{-2x}(-2ln(x)-2)
What is the first derivative of 3x^{-2x} ?
The first derivative of 3x^{-2x} is 3x^{-2x}(-2ln(x)-2)