What is the integral of xsqrt(3-x) ?

The integral of xsqrt(3-x) is 2/5 (3-x)^{5/2}-2(3-x)^{3/2}+C

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integral of xsqrt(3-x)

\int x 3 - x d x

\frac{2}{5} (3 - x)^{\frac{5}{2}} - 2 (3 - x)^{\frac{3}{2}} + C

Solution steps

\int x 3 - x d x

Apply u-substitution

: \int - (- u + 3) u d u

= \int - (- u + 3) u d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int (- u + 3) u d u

Expand

(- u + 3) u : - u^{\frac{3}{2}} + 3 u

= - \int - u^{\frac{3}{2}} + 3 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (- \int u^{\frac{3}{2}} d u + \int 3 u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 3 u d u = 2 u^{\frac{3}{2}}

= - (- \frac{2}{5} u^{\frac{5}{2}} + 2 u^{\frac{3}{2}})

Substitute back

u = 3 - x

= - (- \frac{2}{5} (3 - x)^{\frac{5}{2}} + 2 (3 - x)^{\frac{3}{2}})

Simplify

= \frac{2}{5} (3 - x)^{\frac{5}{2}} - 2 (3 - x)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (3 - x)^{\frac{5}{2}} - 2 (3 - x)^{\frac{3}{2}} + C

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What is the integral of xsqrt(3-x) ?
The integral of xsqrt(3-x) is 2/5 (3-x)^{5/2}-2(3-x)^{3/2}+C