What is the derivative of 2-4cos(x) ?

The derivative of 2-4cos(x) is 4sin(x)

What is the first derivative of 2-4cos(x) ?

The first derivative of 2-4cos(x) is 4sin(x)

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\frac{d}{d x} (2 - 4 cos (x))

4 sin (x)

Solution steps

\frac{d}{d x} (2 - 4 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) - \frac{d}{d x} (4 cos (x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (4 cos (x)) = - 4 sin (x)

= 0 - (- 4 sin (x))

Simplify

= 4 sin (x)

y^{^{'}} = \frac{x y}{1 - x ^{2}}

f (x) = cos (x^{3})

\frac{2 x}{x ^{2} + y ^{2}}

\frac{90 t ^{2}}{t ^{2} + 150}

n = 1 \sum \infty \frac{cos ( n ) + 2}{n}

What is the derivative of 2-4cos(x) ?
The derivative of 2-4cos(x) is 4sin(x)
What is the first derivative of 2-4cos(x) ?
The first derivative of 2-4cos(x) is 4sin(x)