What is the tangent of-x^3(-1.1) ?

The tangent of-x^3(-1.1) is y=3.3a_{0}^2x-(11a_{0}^3)/5

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tangent of-x^3(-1.1)

tangent of

- x^{3} (- 1.1)

y = 3.3 a_{0}^{2} x - \frac{11 a _{0}^{3}}{5}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 1.1 a_{0}^{3})

Find the slope of

y = - x^{3} (- 1.1) : \frac{d y}{d x} = 3.3 x^{2}

Compute the slope of

y = - x^{3} (- 1.1)

x = a_{0} : m = 3.3 a_{0}^{2}

Find the line with slope m=

3.3 a_{0}^{2}

and passing through

(a_{0}, 1.1 a_{0}^{3}) : y = 3.3 a_{0}^{2} x - \frac{11 a _{0}^{3}}{5}

y = 3.3 a_{0}^{2} x - \frac{11 a _{0}^{3}}{5}

ln (1 + x^{2})

\frac{\partial}{\partial y} (6 y^{2} e^{6 x y})

\frac{d}{d x} (x^{4} - 12 x^{3} + 48 x^{2} - 64 x)

\int \frac{x - 1}{( 2 x + 5 ) ( x - 8 )} d x

\int \frac{1}{t ^{2} 289 - t ^{2}} d t

What is the tangent of-x^3(-1.1) ?
The tangent of-x^3(-1.1) is y=3.3a_{0}^2x-(11a_{0}^3)/5