What is the derivative of (-4x^2+9^2) ?

The derivative of (-4x^2+9^2) is -16x(-4x^2+9)

What is the first derivative of (-4x^2+9^2) ?

The first derivative of (-4x^2+9^2) is -16x(-4x^2+9)

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\frac{d}{d x} ((- 4 x^{2} + 9)^{2})

- 16 x (- 4 x^{2} + 9)

Solution steps

\frac{d}{d x} ((- 4 x^{2} + 9)^{2})

Apply the chain rule:

2 (- 4 x^{2} + 9) \frac{d}{d x} (- 4 x^{2} + 9)

= 2 (- 4 x^{2} + 9) \frac{d}{d x} (- 4 x^{2} + 9)

\frac{d}{d x} (- 4 x^{2} + 9) = - 8 x

= 2 (- 4 x^{2} + 9) (- 8 x)

Simplify

= - 16 x (- 4 x^{2} + 9)

\frac{d}{d y} (x cos (x) y)

\int \frac{( sin ^{2} ( x ) )}{x ^{2}} d x

\frac{x ^{2} + 2 x - 8}{x - 1}

\int \frac{a ^{l n (x)}}{x} d x

\frac{1}{1 - 5 x ^{2}}

What is the derivative of (-4x^2+9^2) ?
The derivative of (-4x^2+9^2) is -16x(-4x^2+9)
What is the first derivative of (-4x^2+9^2) ?
The first derivative of (-4x^2+9^2) is -16x(-4x^2+9)