What is the derivative of 1/(1-5x^2) ?

The derivative of 1/(1-5x^2) is (10x)/((1-5x^2)^2)

What is the first derivative of 1/(1-5x^2) ?

The first derivative of 1/(1-5x^2) is (10x)/((1-5x^2)^2)

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derivative of

\frac{1}{1 - 5 x ^{2}}

\frac{10 x}{( 1 - 5 x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{1 - 5 x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((1 - 5 x^{2})^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - 5 x ^{2} ) ^{2}} \frac{d}{d x} (1 - 5 x^{2})

= - \frac{1}{( 1 - 5 x ^{2} ) ^{2}} \frac{d}{d x} (1 - 5 x^{2})

\frac{d}{d x} (1 - 5 x^{2}) = - 10 x

= - \frac{1}{( 1 - 5 x ^{2} ) ^{2}} (- 10 x)

Simplify

- \frac{1}{( 1 - 5 x ^{2} ) ^{2}} (- 10 x) : \frac{10 x}{( 1 - 5 x ^{2} ) ^{2}}

= \frac{10 x}{( 1 - 5 x ^{2} ) ^{2}}

\frac{d}{d x} (- 2 x)

\int \frac{1}{( x ^{2} - 1 ) ^{3}} d x

y^{^{''}} + \frac{14}{t} y^{^{'}} + \frac{42}{t ^{2}} y = 0

\frac{d ^{2}}{d x ^{2}} (3^{x})

\frac{d}{d x} (sin (e^{x^{2}}) \cdot cos (x))

What is the derivative of 1/(1-5x^2) ?
The derivative of 1/(1-5x^2) is (10x)/((1-5x^2)^2)
What is the first derivative of 1/(1-5x^2) ?
The first derivative of 1/(1-5x^2) is (10x)/((1-5x^2)^2)