What is the derivative of y=(x-1)^3 ?

The derivative of y=(x-1)^3 is 3(x-1)^2

What is the first derivative of y=(x-1)^3 ?

The first derivative of y=(x-1)^3 is 3(x-1)^2

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derivative of

y = (x - 1)^{3}

3 (x - 1)^{2}

Solution steps

\frac{d}{d x} ((x - 1)^{3})

Apply the chain rule:

3 (x - 1)^{2} \frac{d}{d x} (x - 1)

= 3 (x - 1)^{2} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 3 (x - 1)^{2} \cdot 1

Simplify

= 3 (x - 1)^{2}

\int tan (x) ln (cos (x)) d x

\int \frac{x ^{2}}{x ^{2} + 4} d x

y = x^{2} - 1, y = 2 x - 1, y = x + 1

y = \frac{2}{1 + x ^{2}}, (3, 0.2)

x (\frac{d y}{d x}) - y = x^{5} + 1

What is the derivative of y=(x-1)^3 ?
The derivative of y=(x-1)^3 is 3(x-1)^2
What is the first derivative of y=(x-1)^3 ?
The first derivative of y=(x-1)^3 is 3(x-1)^2