What is area y=x^2-1,y=2x-1,y=x+1 ?

The answer to area y=x^2-1,y=2x-1,y=x+1 is No Solution

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x^2-1,y=2x-1,y=x+1

area

y = x^{2} - 1, y = 2 x - 1, y = x + 1

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x^{2} - 1 = 2 x - 1 : x = 2, x = 0

x^{2} - 1 = x + 1 : x = 2, x = - 1

2 x - 1 = x + 1 : x = 2

Curves not bounded

= No Solution

y = \frac{2}{1 + x ^{2}}, (3, 0.2)

x (\frac{d y}{d x}) - y = x^{5} + 1

f (x) = x^{2} - 5 x

x \to 0 + lim (8 sin (x) ln (x))

\int \frac{2 x + 1}{( x ^{2} + x + 1 ) ^{\frac{3}{2}}} d x

What is area y=x^2-1,y=2x-1,y=x+1 ?
The answer to area y=x^2-1,y=2x-1,y=x+1 is No Solution