What is the derivative of f(x)=x^2-5x ?

The derivative of f(x)=x^2-5x is 2x-5

What is the first derivative of f(x)=x^2-5x ?

The first derivative of f(x)=x^2-5x is 2x-5

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derivative of

f (x) = x^{2} - 5 x

2 x - 5

Solution steps

\frac{d}{d x} (x^{2} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5 x) = 5

= 2 x - 5

x \to 0 + lim (8 sin (x) ln (x))

\int \frac{2 x + 1}{( x ^{2} + x + 1 ) ^{\frac{3}{2}}} d x

\int \frac{9 x ^{2} - 26 x - 5}{3 x ^{2} - 5 x - 2} d x

sin (7 t + 4)

\int \frac{1}{6 x + 1} d x

What is the derivative of f(x)=x^2-5x ?
The derivative of f(x)=x^2-5x is 2x-5
What is the first derivative of f(x)=x^2-5x ?
The first derivative of f(x)=x^2-5x is 2x-5