What is the integral from-infinity to 0 of 1/(4-2x) ?

The integral from-infinity to 0 of 1/(4-2x) is diverges

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integral from-infinity to 0 of 1/(4-2x)

\int_{- \infty}^{0} \frac{1}{4 - 2 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{4 - 2 x} d x

Compute the indefinite integral:

\int \frac{1}{4 - 2 x} d x = - \frac{1}{2} ln ∣ 4 - 2 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{4 - 2 x} d x =

diverges

= diverges

\int_{0.5}^{t + 4} 3 d x

\int_{- 1}^{3} (4 - 2 x) d x

\int_{0}^{9} k (9 - x)

\frac{d}{d x} (arctan (\frac{a ^{2} - x ^{3}}{b ^{2}}))

\frac{d}{d x} (x \cdot (x^{5} + x^{4} + 3 x + 2))

What is the integral from-infinity to 0 of 1/(4-2x) ?
The integral from-infinity to 0 of 1/(4-2x) is diverges