What is the integral of 1/8 sin(8x) ?

The integral of 1/8 sin(8x) is -1/64 cos(8x)+C

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integral of 1/8 sin(8x)

\int \frac{1}{8} sin (8 x) d x

- \frac{1}{64} cos (8 x) + C

Solution steps

\int \frac{1}{8} sin (8 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int sin (8 x) d x

Apply u-substitution

: \int sin (u) \frac{1}{8} d u

= \frac{1}{8} \cdot \int sin (u) \frac{1}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \frac{1}{8} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{8} \cdot \frac{1}{8} (- cos (u))

Substitute back

u = 8 x

= \frac{1}{8} \cdot \frac{1}{8} (- cos (8 x))

Simplify

\frac{1}{8} \cdot \frac{1}{8} (- cos (8 x)) : - \frac{1}{64} cos (8 x)

= - \frac{1}{64} cos (8 x)

Add a constant to the solution

= - \frac{1}{64} cos (8 x) + C

\int \frac{5}{x} d x

g (x) = 6 x + 8

\int 2 x - y d x

x^{2} y^{^{'}} + y^{^{'}} = x y

y = x^{2} + 30 x + 225, y = 17 (x + 15)

What is the integral of 1/8 sin(8x) ?
The integral of 1/8 sin(8x) is -1/64 cos(8x)+C