What is the integral from 4 to 9 of 2sqrt(x) ?

The integral from 4 to 9 of 2sqrt(x) is 76/3

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integral from 4 to 9 of 2sqrt(x)

\int_{4}^{9} 2 x d x

\frac{76}{3}

Decimal

25.33333 \dots

Solution steps

\int_{4}^{9} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= 2 [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= 2 \cdot \frac{38}{3}

Simplify

= \frac{76}{3}

n = 1 \sum \infty \frac{n ^{2}}{2 n ^{2}}

y = 4 x^{2} sin (x) tan (x)

y^{^{'}} = \frac{1}{t y + 2 t + y + 2}

n \to a lim (\frac{5 n}{10 n + 4})

\frac{d}{d x} (5 - cos (x))

What is the integral from 4 to 9 of 2sqrt(x) ?
The integral from 4 to 9 of 2sqrt(x) is 76/3