What is the derivative of sin(x^3-x) ?

The derivative of sin(x^3-x) is cos(x^3-x)(3x^2-1)

What is the first derivative of sin(x^3-x) ?

The first derivative of sin(x^3-x) is cos(x^3-x)(3x^2-1)

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\frac{d}{d x} (sin (x^{3} - x))

cos (x^{3} - x) (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (sin (x^{3} - x))

Apply the chain rule:

cos (x^{3} - x) \frac{d}{d x} (x^{3} - x)

= cos (x^{3} - x) \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= cos (x^{3} - x) (3 x^{2} - 1)

2 y = x, x + 1 = (y - 1)^{2}

\frac{d}{d x} (7 - 8 x)

\frac{d y}{d x} = (x + y + 5)^{2}

y^{^{''}} + 2 y = - 4 x

2 e^{- t} cos (4 t)

What is the derivative of sin(x^3-x) ?
The derivative of sin(x^3-x) is cos(x^3-x)(3x^2-1)
What is the first derivative of sin(x^3-x) ?
The first derivative of sin(x^3-x) is cos(x^3-x)(3x^2-1)