What is (\partial)/(\partial y)(3x^2y^2) ?

The answer to (\partial)/(\partial y)(3x^2y^2) is 6x^2y

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(\partial)/(\partial y)(3x^2y^2)

\frac{\partial}{\partial y} (3 x^{2} y^{2})

6 x^{2} y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x^{2} \cdot 2 y^{2 - 1}

Simplify

= 6 x^{2} y

y^{^{'}} + \frac{1}{x} y = 3 x^{2}

x \to 3 lim (5 x - 1)

\frac{d y}{d x} = \frac{e ^{x}}{2 + e ^{x}}

\int \frac{19 x e ^{2 x}}{( 1 + 2 x ) ^{2}} d x

\frac{d}{d x} (6 x + sin (3 x))

What is (\partial)/(\partial y)(3x^2y^2) ?
The answer to (\partial)/(\partial y)(3x^2y^2) is 6x^2y