What is the derivative of y=arcsin(x+1) ?

The derivative of y=arcsin(x+1) is 1/(sqrt(-x^2-2x))

What is the first derivative of y=arcsin(x+1) ?

The first derivative of y=arcsin(x+1) is 1/(sqrt(-x^2-2x))

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derivative of

y = arcsin (x + 1)

\frac{1}{- x ^{2} - 2 x}

Solution steps

\frac{d}{d x} (arcsin (x + 1))

Apply the chain rule:

\frac{1}{1 - ( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= \frac{1}{1 - ( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{1 - ( x + 1 ) ^{2}} \cdot 1

Simplify

\frac{1}{1 - ( x + 1 ) ^{2}} \cdot 1 : \frac{1}{- x ^{2} - 2 x}

= \frac{1}{- x ^{2} - 2 x}

\int \frac{2}{3} x^{\frac{3}{2}} - 9 sin (x) d x

\frac{\partial}{\partial x} (7 x sin (y - z))

\int 3 x^{2} - 2 y^{2} d x

\int \frac{x}{1 - 2 x} d x

What is the derivative of y=arcsin(x+1) ?
The derivative of y=arcsin(x+1) is 1/(sqrt(-x^2-2x))
What is the first derivative of y=arcsin(x+1) ?
The first derivative of y=arcsin(x+1) is 1/(sqrt(-x^2-2x))