What is the derivative of y=8^x ?

The derivative of y=8^x is 3ln(2)*8^x

What is the first derivative of y=8^x ?

The first derivative of y=8^x is 3ln(2)*8^x

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derivative of

y = 8^{x}

3 ln (2) \cdot 8^{x}

Solution steps

\frac{d}{d x} (8^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 8^{x} ln (8)

Simplify

ln (8) : 3 ln (2)

= 3 ln (2) \cdot 8^{x}

\int \frac{1 - 2 x - x ^{2}}{x ^{3} + x ^{2} - 3 x + 1} d x

x \to 3 lim (\frac{- x + 6}{- 2 - 1})

\frac{d}{d x} (k x e^{x})

x \to 2 lim (x^{2} + 5 x)

sin (x) e^{c o s (x)}

What is the derivative of y=8^x ?
The derivative of y=8^x is 3ln(2)*8^x
What is the first derivative of y=8^x ?
The first derivative of y=8^x is 3ln(2)*8^x