What is the derivative of kxe^x ?

The derivative of kxe^x is k(e^x+e^xx)

What is the first derivative of kxe^x ?

The first derivative of kxe^x is k(e^x+e^xx)

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\frac{d}{d x} (k x e^{x})

k (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (k x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= k \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= k (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= k (1 \cdot e^{x} + e^{x} x)

Simplify

= k (e^{x} + e^{x} x)

x \to 2 lim (x^{2} + 5 x)

sin (x) e^{c o s (x)}

\int sin (7 x + 1) d x

\frac{\partial}{\partial y} (e^{- 2 x} cos (4 y))

- \frac{7}{( x - 7 ) ^{2}}

What is the derivative of kxe^x ?
The derivative of kxe^x is k(e^x+e^xx)
What is the first derivative of kxe^x ?
The first derivative of kxe^x is k(e^x+e^xx)