What is (\partial)/(\partial y)(e^{-2x}cos(4y)) ?

The answer to (\partial)/(\partial y)(e^{-2x}cos(4y)) is -4e^{-2x}sin(4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(e^{-2x}cos(4y))

\frac{\partial}{\partial y} (e^{- 2 x} cos (4 y))

- 4 e^{- 2 x} sin (4 y)

Solution steps

\frac{\partial}{\partial y} (e^{- 2 x} cos (4 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 2 x} \frac{\partial}{\partial y} (cos (4 y))

Apply the chain rule:

- sin (4 y) \frac{\partial}{\partial y} (4 y)

= - sin (4 y) \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (4 y) = 4

= e^{- 2 x} (- sin (4 y) \cdot 4)

Simplify

= - 4 e^{- 2 x} sin (4 y)

- \frac{7}{( x - 7 ) ^{2}}

\frac{\partial}{\partial y} (e^{x} - e^{x^{2}})

4 x^{2} + 9

\int (7 x + cos (x)) d x

\frac{d y}{d x} + \frac{2}{x} y = \frac{1}{x ^{2}}

What is (\partial)/(\partial y)(e^{-2x}cos(4y)) ?
The answer to (\partial)/(\partial y)(e^{-2x}cos(4y)) is -4e^{-2x}sin(4y)