What is the solution for (dy)/(dx)=(x^3+4y^3)/(3xy^2) ?

The solution for (dy)/(dx)=(x^3+4y^3)/(3xy^2) is y=x\sqrt[3]{-1+c_{1}x}

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(dy)/(dx)=(x^3+4y^3)/(3xy^2)

\frac{d y}{d x} = \frac{x ^{3} + 4 y ^{3}}{3 x y ^{2}}

y = x 3 - 1 + c_{1} x

Solution steps

\frac{d y}{d x} = \frac{x ^{3} + 4 y ^{3}}{3 x y ^{2}}

Solve Bernoulli ODE:

y = x 3 - 1 + c_{1} x

y = x 3 - 1 + c_{1} x

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\int_{0}^{8} 1

x \to 3 lim (x^{2} - 4 x + 10)

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\int \frac{x - 1}{x ^{2} + x - 6} d x

What is the solution for (dy)/(dx)=(x^3+4y^3)/(3xy^2) ?
The solution for (dy)/(dx)=(x^3+4y^3)/(3xy^2) is y=x\sqrt[3]{-1+c_{1}x}