What is the sum from n=0 to infinity of 1.002^n ?

The sum from n=0 to infinity of 1.002^n is diverges

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sum from n=0 to infinity of 1.002^n

n = 0 \sum \infty 1.00 2^{n}

diverges

Solution steps

n = 0 \sum \infty 1.00 2^{n}

Apply Series Geometric Test:

diverges

= diverges

h \to + 0 lim (6 x + 3 h)

\int_{0}^{2} x e^{x^{2}} d x

\int \frac{3 x ^{2} - 7}{x ^{3}} d x

y = x + 2, y = - 1, x = 2, x = 5

9 z - 8

What is the sum from n=0 to infinity of 1.002^n ?
The sum from n=0 to infinity of 1.002^n is diverges