What is the tangent of f(x)=3x^4+2x-1,(2,51) ?

The tangent of f(x)=3x^4+2x-1,(2,51) is y=98x-145

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tangent of f(x)=3x^4+2x-1,(2,51)

tangent of

f (x) = 3 x^{4} + 2 x - 1, (2, 51)

y = 98 x - 145

Solution steps

Find the slope of

f (x) = 3 x^{4} + 2 x - 1 : \frac{df ( x )}{d x} = 12 x^{3} + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 98

Find the line with slope m=

98

and passing through

(2, 51) : y = 98 x - 145

y = 98 x - 145

\int (tan (x))^{7} (sec (x))^{2} d x

x \to 0 + lim (\frac{1}{x} \cdot sin (\frac{1}{x}))

\frac{\partial}{\partial x} (4 ln (x y))

x^{3} - 6 x^{2} - 34 x + 40, at x = 6

\int - k x d x

What is the tangent of f(x)=3x^4+2x-1,(2,51) ?
The tangent of f(x)=3x^4+2x-1,(2,51) is y=98x-145