What is the solution for (x^3+y^3)dx+3xy^2dy=0 ?

The solution for (x^3+y^3)dx+3xy^2dy=0 is y=\sqrt[3]{-(x^3)/4+(c_{1})/x}

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(x^3+y^3)dx+3xy^2dy=0

(x^{3} + y^{3}) d x + 3 x y^{2} d y = 0

y = 3 - \frac{x ^{3}}{4} + \frac{c _{1}}{x}

Solution steps

(x^{3} + y^{3}) d x + 3 x y^{2} d y = 0

Solve Bernoulli ODE:

y = 3 - \frac{x ^{3}}{4} + \frac{c _{1}}{x}

y = 3 - \frac{x ^{3}}{4} + \frac{c _{1}}{x}

\frac{d}{d x} ((8 x + 7)^{2})

\int \frac{1}{cos ( 3 x )} d x

- 9 x^{\frac{1}{2}} + x^{\frac{3}{2}}

(4, - 8), (8, 5)

\frac{d}{d x} (3 x^{4})

What is the solution for (x^3+y^3)dx+3xy^2dy=0 ?
The solution for (x^3+y^3)dx+3xy^2dy=0 is y=\sqrt[3]{-(x^3)/4+(c_{1})/x}