What is derivative of f(x)= 1/2 (7t^2+t)^{-3} ?

The answer to derivative of f(x)= 1/2 (7t^2+t)^{-3} is (dt)/(dx)=0

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derivative of f(x)= 1/2 (7t^2+t)^{-3}

derivative of

f (x) = \frac{1}{2} (7 t^{2} + t)^{- 3}

\frac{d t}{d x} = 0

Solution steps

f (x) = \frac{1}{2} (7 t^{2} + t)^{- 3}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{3 ( 14 t \frac{d t}{d x} + \frac{d t}{d x} )}{2 ( 7 t ^{2} + t ) ^{4}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int_{- \infty}^{0} e^{2 x} d x

\frac{r}{r ^{2} + 2}

\frac{\partial}{\partial x} (x^{2} + y^{2} - y^{2} x - 8)

\int 2 x - \frac{2}{x} d x

\frac{\partial}{\partial y} (x arctan (\frac{y}{z}))

What is derivative of f(x)= 1/2 (7t^2+t)^{-3} ?
The answer to derivative of f(x)= 1/2 (7t^2+t)^{-3} is (dt)/(dx)=0